35.What is the best title of the passage?A.Space-bred Seeds Offer Great Chances食尼卡常，行辆头)朋应有看·合脑三润B.Chang'e 5 Returns with a Big PackageC.Plant Mutations Result in a Better LifeD.Seeds from Space Mark a New History第二节（共5小题；每小题2.5分，满分12.5分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。选项中有两项为多余选项。Human bodies were actually designed for walking,a wonderful form of exerciseat no cost.It's kind to our bodies and great for our waistlines.36Probably you already love to walk,but you're getting bored of tracing the sameold route day after day,or maybe you're new to walking and aren't sure how to getstarted.37 Ask yourself,what do you want to get out of walking aside from thehealth benefits?Do you want to meet other people?See new places?Get out into thecountryside or explore a new city?Knowing your goals will help you decide on thetype of walk you want to do.Call up your friends and schedule walks with them if socializing is your aim.38 Many malls have groups that come every day,or every weekend,to "walk themall".These groups are always happy to include one more walker!39Many large cities haye ineredible gardens and parks that include quietwalking trails getting you off the beaten path.Thanks to the Rails to Trails program,railways across the country are being transformed into scenic walking paths that are aperfect way to seek calmness.From the benefits to your heart to your overall happiness,walking is just plaingood for you.40 It's a fantastic way to get to know a place by the power of yourown two feet.oniudinoo8A.This month,pick up a map and start walking.bos.AB.Ask your friends where they like to walk and just go there.slbnsdA8C.You may as well consider heading to a new city for a change.D.Either way,it's time to accept the idea of walking with a purpose.E.Recently,science has proved that walking is good for your body shape.F.And best of all,it's a great way to see new things and meet new people!G.If you're after walking alone,ask about local hikes that get you away from thecrowd.英语试题（长那版）第9页（共12页）

设AM=x,BM=2x,在Rt△ABM中，AB2+AMP=BMP,.32十x2=4x2,解得x=√3，.AM=3.…8分M②证明：如图，延长DA至点E,使AE=AM,连接BE∠ADC=90°，∠MBC=90°，∴.∠MDC+∠MBC=180°，.M,B,C,D四点共圆，∴.∠MDB=∠MCB.9分.∠DAB=90°，AE=AM,∴.BE=BM,∠E=∠BME..MB平分∠AMC,∴.∠AMB=∠CMB,.∠E=∠CMB.10分.∠E=∠CMB,∠ADB=∠MCB,BE=BM,'.△DEB≌△CMB(AAS),∴.MC=DE=DM+2AM……12分23.解：(1)将(2，-3)，(-2,3)代入y=ax2+bx+2,(-3=4a+2b+2得(3=4a-2b+2a=-.12解得b=一2“抛物线的表达式为y=一22-Γ2x+2.3分(2i证明：y=7-多2x+2,当x=0时，y=2..C点坐标为(0,2).令-是x+2=0,解得万=-4=1，∴.A点坐标为（一4,0），B点坐标为(1,0)，.AB=1-(-4)=5,BC=√22+1=√5，AC=√/42+22=2W5..AC+BC=25,AB2=25,∴.AC2+BC2=AB2,∠ACB=90°.6分.∠ACO+∠BCO=90°，∠BCO+∠CBO=90°，【九年级数学·参考答案第4页（共5页）】

所以点C的坐标为(a,+3小点D的坐标为(a,a).所以a-（a+3=3.解得a=424.(1)如图所示，△4，BC,即为所求：(2)Sm=3×5-号×5x2-2×2×1-号×3×3=2(3)△A:B,C内部所有的整点坐标为(2,2)，(2,1),(3.0)A2BB-4-224第24题图25.(1)2,2(2)如图所示：Y5-6-5-4-3-2-102346782第25题图(3)B.选做题26.(1)-7(2)减.(3)证明：设<<0，f)-f)=2x-12x,-1=(24,-)-x(2x,-)(x2x,x,(x2-)+(,+x)(x-x）(x尸因为<2<0，所以2>0,2-1>0,1+2<0，-<0.2(-x)+(6+x=>0.所(x2月即f(x)-八2)>0.所以f八)>八2).所以fx)=2x1(x<0)是减数。x27.(1)对丁y=-2x+2,令x=0,则y=2.所以点B的坐标为(0,2).(2)对于y=-2x+2,令y=0,则x=1.所以点A的坐标为(1,0).所以OA=1.所以5m=30A·y=3×1×(-2x+2)=-x+1,即S=-x+1(0

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1、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

A。(的图象关于直线x=-径对称B.f的图象关于点(0中心对称C.将函数y=5sin2x-cos2x的图象向左平移个单位得到函数/(x)的图象D.若方程/八)=m在[受0上有两个不相等的实数根，则m的

2、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

3、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、 国考1号1(第1套)2024届高三暑期补课检测(一)1物理答案

(2)

4、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

A。(的图象关于直线x=-径对称B.f的图象关于点(0中心对称C.将函数y=5sin2x-cos2x的

5、[国考1号15]第15套 高中2023届高考适应性考试理科数学答案

1、 国考1号1(第1套)2024届高三暑期补课检测(一)1物理答案

(2)在竖直方向上，根据y=1=gT,解得T=,区，水平方向有x=2L=T,解得。=2VgL。(3》点的

共有12种等可能的结果，其中这两张卡片正面图案呈现的现象恰好恰好一个属于化学变化一个属于物理变化有：AB,AC,BA,BD,CA,CD,DB,DC,共8种，·这两张卡片正面图案呈现的现象恰好个网于化学变化个屏于物理变化的概率为吕-号故选：D.9.解：由题知，二次函数y=-x2+2x-3的图象开口向下，故A选项错误，当x=0时，y=-3,以图象与y轴的交点坐标为(0，-3).故B选项错误因为y=-x2+2x-3=-(x-1)2-2,所以当x=1时，函数有最大值为-2.故C选项正确因为抛物线的对称轴为直线x=1,且开口向下，所以当x>1时，y随x的增大而减小故D选项错误，故选：C10.解：由题意可知，当点P从点B运动到点D时，△ADP的面积由大变小，到点D时，面积最小为0；当点P在点B时，S△p=6,即2AB·AD=6;当点P从点D运动到点C时，△ADP的面积由小变大，到点C时，面积最大为6；当点P从点C运动到点B时，△ADP的面积保持不变，此时x=BD+DC+CB=12.根据矩形的性质可知∠BCD=90°，且BC=AD,AB=CD,.CD.BG6..CD·BC=12.在Rt△BCD中，BC2+CD2=BD2∴.(BC+CD)2-2BC·CD=BD2..（12-BD)2-24=BD2..解得BD=5rCD·BC=12联立lCD+BC=7’[CD=3 [CD=4解得或BC=4BC=3又BC>AB,∴.BC=4.数学中考导航冲刺押题卷参考答案（四）第2页，共8页