榆林市2022-2023年度高三第二次模拟检测(23-338C)理综答案试卷 答案(更新中)

榆林市2022-2023年度高三第二次模拟检测(23-338C)理综答案试卷 答案(更新中)，目前全国100所名校答案网已经汇总了榆林市2022-2023年度高三第二次模拟检测(23-338C)理综答案试卷 答案(更新中)的各科答案和试卷，更多全国100所名校答案请关注本网站。

书面表达One possible version:Dear Mike,Our English Drama Club plans to hold an English drama show next week,and on behalfof the club,I'm writing to invite you to watch it.The 2-hour show will take place in the school hall at 3:00 pm next Saturday.Themembers of our club will perform the highlights of William Shakespeare's Hamlet,which iswell-known to most Chinese people.If it is convenient for you next Saturday afternoon,please be present.We wouldappreciate it if you could give us some advice on improving our performance.We're lookingforward to your arrival.Yours sincerely,Li Hua

19.(12分)0如图，在圆柱O1O2中，AB,CD分别是上、下底面圆的直径，且AB∥CD,EF,GH分别G是圆柱轴截面上的母线(1)若CE=DE=2√6，圆柱的母线长等于底面圆的直径，求圆柱的表面积；(2)证明：平面ABH∥平面ECD(1)解：连接CF,DF如图.H因为DE=CE,EF⊥CF,EF⊥DF,所以△CEF≌△DEF,所以CF=DF,安的壁全面个心如西：收上因为CD为直径，记底面半径为R,EF=2R,则CF2十DF2=4R2,所以DF=√2R.8)平)，发又因为DF2十EF2=DE2,所以（√2R)十(2R)2=(2√6）2，解得R=2,©，销共限919P所以圆柱的表面积S=2πRX2R十2πR2=24π.人A面平面平出，G0重出餐。大0，A面平Q1B,点随人@网)(2)证明：连接O1E,O2H,O1H,O2E,如图」由圆柱性质知GH∥EF且GH=EF,所以GE∥HF,O1E∥O2H且O1E=O2H,所以四边形HO2EO1为平行四边形，所以O1H∥O2E.0西0可鱼牛，M平交必0为9)好用T4又因为O1H中平面CDE,O2EC平面CDE,所以O1H∥平面CDE,同理AB∥平面CDE.又因为AB∩O1H=O1,O1HC平面ABH,ABC平面ABH,所以平面ABH∥平面ECD.