山东省2023届高三下学期3月新高考联合质量测评试题地理答案

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山东省2023届高三下学期3月新高考联合质量测评试题地理答案,目前全国100所名校答案网已经汇总了山东省2023届高三...

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第二节故事文本分析)本篇读后续写的主题为人与自然。短文讲述了Lus在去年的钓鱼大赛中失利,今年决定一雪前耻的故事。在今年的钓鱼大赛中,所有参加选手都挤在湖边,十分吵闹,而Ls远离人群,独自找了一个安静的地方垂钓,最终他会钓起大鱼并成为冠军吗?从文章所给的提示语可知,Luis成功了。文章的前两段介绍了Lis和父亲早起为钓鱼大赛做的准备活动,交代了故事的人物和背景。文章第三段开始对钓鱼大赛的现场进行描写,同时设下悬念:“WouldLuis's totally secret plan help him win a prize?(Luis的绝密计划能否帮助他赢得奖品?)”。文章第四段和第五段交代了比赛规则和比赛开始后的现场情况。最后一段则讲述了Luis安静地等待大鱼上钩的情况。写作思路点拨)题】由续写部分第一段给出的开头语“Suddenly,a hugefish bit and pulled hard at the worm on Luis's fishing line.(突然,一条大鱼上钩了并用力地拉扯Lis鱼线上的虫饵。)”可知,续写部分可以围绕Luis把鱼钓上来的过程以及鱼钓上来后发生的事情展开。由续写部分第二段给出的开头语“Dad was so happy.‘What was your secret plan,Luis?'(爸爸非常开心。Luis,你的秘密计划是什么?’)”可知,Luis已经成功钓起大鱼,第二段的续写可以围绕Lus的秘密计划到底是什么来展开。【参考范文】Suddenly,a huge fish bit and pulled hard at the wormon Luis's fishing line.Luis felt his pole so heavy and knew itwas a big fish.Very carefully,he pulled it back and caughtthe most enormous fish he'd ever seen.Chief Dugan racedover and measured the beautiful silver fish,and then slippedit back into the water.Undoubtedly,it was the biggest onefished that day.Over the speaker,he declared that the DeerLake Fishing Derby was over and announced that Luis wasthe lucky winner.So Luis won the grand prize-a new bike!Overwhelmed with joy,Luis rode the bike to his father'sburger stall and told his father that his secret plan worked.Dad was so happy."What was your secret plan,Luis?"With a smile on his face,Dad flipped hamburgers on the hotgrill and asked,"Did you use a lucky worm or your specialfishing lure?"Luis grinned and climbed on his shiny newbike."I waited until the noisy kids frightened all the fish overto me,"he said."And they sure did.Fish are quiet animals,and too much noise will scare them off.I learned this lessonlast year.So this year I decided to fish alone,far away fromthe crowd.My super-secret plan worked!"亮点评析)》(1)本篇范文中作者创设了丰富、合理的内容,使情节发晨富有逻辑性,续写完整且与原文情景融洽度高。(2)作者使用了丰富且恰当的词汇和语法结构,语言地道且表达流畅。(3)作者自然地使用了段间、句间衔接,全文结构清嘶,前后呼应,意义连贯。

18.【命题意图】本题考查离散型随机变量的分布列与期望、条件概率的求解,体现了数据分析、数学运算等核心素养【解】(1)X的可能取值为0,1,2(1分)由题意,得PX=0)=()号Px=1)=cx*号号,Px=2)-()-若(4分).X的分布列为X0121242525(5分)(0=01号2培-号9(6分)(2)记第i局甲获胜,乙获胜,平局分别为事件C:,D,E(i=1,2,3),A =(E C2C3)U (C E2Cs U E D2D3 U(DE2D3),(7分)》a=子+号×号×号号阳°+写×号×号塔(9分)】)=得号号号(11分)16..P(BIA)=P(AB)125P(A)45(12分)25

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