[泉州三检]泉州市2023届高中毕业班质量监测(三)3数学试卷 答案(更新中)

[泉州三检]泉州市2023届高中毕业班质量监测(三)3数学试卷 答案(更新中)，目前全国100所名校答案网已经汇总了[泉州三检]泉州市2023届高中毕业班质量监测(三)3数学试卷 答案(更新中)的各科答案和试卷，更多全国100所名校答案请关注本网站。

11.(6分)(1)图见解析(2分)(2)减小(1分)右(1分)(3)1192(2分)【考查点】本题考查描绘二极管伏安特性曲线实验。【解析】(1)描绘二极管的伏安特性曲线，电压要求从0开始进行测量，故滑动变阻器要采用分压式接法：由超查可知二极管电阻数最级为10，则有尽名，放电流表应采用外接法，如图所示。一<(2)结合题图2，伏安特性曲线上的点与原点连线的斜率表示电阻的倒数，随着电流的增加，斜率增大，即电阻减小；根据并联分流原理，测量时，二极管电流的测量值比真实值要大，故二极管的实际的伏安特性曲线要略微向右移。(3)二极管的最佳工作电压为2.5V,现用5.0V的稳压电源(内阻不计)供电，根据题图2可知，二极管处于最佳工作状态时，电路中的电流约为21A,根据闭合电路欧姆定律和电路结构可得串联电阻R的阻值为R=5,0-2.5≈1192.0.021

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